Nama : Safitri Npm : 0953010008 Progdi : Teknik Sipil Mata Kuliah : Matematika Rekayasa II Dosen : Ir. Hendrata Wibisana,.MT
1. Diketahui :
x | y |
1 | 1.8 |
2 | 2.8 |
3 | 3.8 |
4 | 5.8 |
5 | 9 |
6 | 14.8 |
Ditanya : Buatlah model : Y = ax2 + bx Y = ax2 + bx + c Y = ax3 + bx2 + cx + d Jawab :
| x | y | x² | x³ | x⁴ | x⁵ | x⁶ | xy | x²y | x³y |
| 1 | 1.8 | 1 | 1 | 1 | 1 | 1 | 1.8 | 1.8 | 1.8 |
| 2 | 2.8 | 4 | 8 | 16 | 32 | 64 | 5.6 | 11.2 | 22.4 |
| 3 | 3.8 | 9 | 27 | 81 | 243 | 729 | 11.4 | 34.2 | 102.6 |
| 4 | 5.8 | 16 | 64 | 256 | 1024 | 4096 | 23.2 | 92.8 | 371.2 |
| 5 | 9 | 25 | 125 | 625 | 3125 | 15625 | 45 | 225 | 1125 |
| 6 | 14.8 | 36 | 216 | 1296 | 7776 | 46656 | 88.8 | 532.8 | 3196.8 |
∑ | 21 | 38 | 91 | 441 | 2275 | 12201 | 67171 | 175.8 | 897.8 | 4819.8 |
jadi nilai a = 0.333, b = 0.32è Y = 0.333x2+ 0.32x
jadi nilai a = 0.586, b = -1.654, c = 3.24 è Y = 0.586x2 – 1.654x + 3.24
jadi nilai a = 130.857, b = -1.395 x 103, c = 4.298 x 103, d = -3.496 x 103 è Y = 130.857x3 – 0.001395x2 + 0.004298x – 0.003496 | 
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