Kamis, 17 Maret 2011

Nama : Safitri
Npm : 0953010008
Progdi : Teknik Sipil
Mata Kuliah : Matematika Rekayasa II
Dosen : Ir. Hendrata Wibisana.,MT

Tugas
X
Y
X2
XY
1
1.8
1
1.8
2
3.8
4
7.6
3
5.8
9
17.4
4
8.8
16
35.2
5
12.8
25
64
∑X = 15
∑Y = 33
∑X2 =55
∑XY = 126

Hasil :
o                              ∑XY = a∑X2 + b∑X
126 = 55a + 15b ………….(1)
o                                  ∑Y = a∑X + nb
              33 = 15a + 5b …………..(2)

o      Subsitusi pers 1 dan 2 :
126 = 55a + 15b   x 1        55a + 15b = 126
  33 = 15a + 5b     x 3        45a + 15 b = 99
                                                  10a = 27
                                                     a = 2.7
o        Eliminasi pers 1 :
      15a + 5b = 33
15 (2.7) + 5b = 33
     40.5 + 5b = 33
               5b = 33 – 40.5
               5b = -7.5
                 b = -1.5
Jadi model matematik = Y = ax + b = 2.7 – 1.5


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