Selasa, 22 Maret 2011

TUGAS MATEMATIKA REKAYASA 2 ke-1

Nama : Ishlahul Baqo
Npm : 0953010058 (55)

Tugas


X Y X2 XY
1 1.8 1 1.8
2 3.8 4 7.6
3 5.8 9 17.4
4 8.8 16 35.2
5 12.8 25 64
∑X = 15 ∑Y = 33 ∑X2 =55 ∑XY = 126



Hasil :

o ∑XY = a∑X2 + b∑X
126 = 55a + 15b ………….(1)


o ∑Y = a∑X + nb
33 = 15a + 5b …………..(2)

o Subsitusi pers 1 dan 2 :
126 = 55a + 15b x 1 55a + 15b = 126
33 = 15a + 5b x 3 45a + 15 b = 99
10a = 27
a = 2.7
o Eliminasi pers 1 :
15a + 5b = 33
15 (2.7) + 5b = 33
40.5 + 5b = 33
5b = 33 – 40.5
5b = -7.5
b = -1.5

Jadi model matematik = Y = ax + b = 2.7 – 1.5


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